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	<title>Physics 09-10</title>
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		<title>Physics 09-10</title>
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		<title>Notes on reading 7.1-7.3</title>
		<link>http://levya11.wordpress.com/2010/02/04/notes-on-reading-7-1-7-3/</link>
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		<pubDate>Thu, 04 Feb 2010 06:15:58 +0000</pubDate>
		<dc:creator>levya11</dc:creator>
				<category><![CDATA[Physics]]></category>
		<category><![CDATA[Chapter 7]]></category>

		<guid isPermaLink="false">http://levya11.wordpress.com/?p=75</guid>
		<description><![CDATA[Chapter 7: Momentum 7.1     Momentum Momentum (Inertia in motion) &#8211; The mass of an object multiplied by its velocity. momentum (mv) = mass • velocity   (p) A moving object can have a large momentum if it&#8217;s mass is large or if it&#8217;s velocity is large or both. Stationary objects have no momentum. 7.2     Impulse Changes [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=levya11.wordpress.com&amp;blog=10571445&amp;post=75&amp;subd=levya11&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><strong>Chapter 7: Momentum</strong></p>
<p><span style="text-decoration:underline;">7.1     Momentum</span></p>
<p>Momentum (Inertia in motion) &#8211; The mass of an object multiplied by its velocity.</p>
<ul>
<li>momentum (mv) = mass • velocity   (p)</li>
<li>A moving object can have a large momentum if it&#8217;s mass is large or if it&#8217;s velocity is large or both.</li>
<li>Stationary objects have no momentum.</li>
</ul>
<p><span style="text-decoration:underline;">7.2     Impulse Changes Momentum</span></p>
<ul>
<li>Mass, velocity, or both have a direct impact on Momentum. If the momentum of an object changes, either the mass, velocity or both have changed.</li>
<li>Force produces acceleration.</li>
<li>The amount of time a force acts on an object is also important.</li>
<li>Quantity force • time interval = Impulse</li>
<li>Impulse = F ∆t</li>
<li>Ft = ∆mv</li>
<li>Impulse-momentum relationship allows us to analyze multiple situations where momentum changes.</li>
</ul>
<p>Increasing momentum &#8211; apply the greatest force possible for the longest time possible.</p>
<ul>
<li>Impact forces = average force of impact.</li>
<li>Impact refers to a force (N)</li>
<li>Impulse refers to impact force • time (Ns)</li>
</ul>
<p>Decreasing momentum &#8211; extend the time of impact in order to reduce the force of the impact.</p>
<ul>
<li>A difference in impact time is important even if you can&#8217;t notice the give in the surface.</li>
</ul>
<p><span style="text-decoration:underline;">7.3     Bouncing</span></p>
<ul>
<li>Impulses are greater when an object bounces.</li>
<li>More impulse is required to make an object completely stop than for the object to change directions.</li>
<li>Lester A. Pelton discovered that the flat paddles on waterwheels were inefficient.</li>
</ul>
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		<title>Collision/Impulse on 2/1</title>
		<link>http://levya11.wordpress.com/2010/02/02/collisionimpulse-on-21/</link>
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		<pubDate>Wed, 03 Feb 2010 03:38:16 +0000</pubDate>
		<dc:creator>levya11</dc:creator>
				<category><![CDATA[Physics]]></category>
		<category><![CDATA[Lab]]></category>

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		<description><![CDATA[Collision &#8211; When two objects interact strongly, but briefly. Result of a collision &#8211; The motion of one or both objects changes drastically during the collision. Rather than attempting to understand the details of a collision, we focus on the total change from initial to final conditions. Lab Simulation Set up: Have a &#8220;frictionless&#8221; track [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=levya11.wordpress.com&amp;blog=10571445&amp;post=71&amp;subd=levya11&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>Collision &#8211; When two objects interact strongly, but briefly.</p>
<p>Result of a collision &#8211; The motion of one or both objects changes drastically during the collision.</p>
<ul>
<li>Rather than attempting to understand the details of a collision, we focus on the total change from initial to final conditions.</li>
</ul>
<p><span style="text-decoration:underline;">Lab Simulation</span></p>
<p>Set up: Have a &#8220;frictionless&#8221; track on a flat surface with a force detector attached to one end and a motion detector attached to the opposite end. Use one of the cars and attach a spring to the end facing the force detector. Zero the force and position JUST before the spring would contact the force detector.</p>
<p>From the data we concluded:</p>
<ul>
<li>Both positive and negative – because the spring compresses a small amount during contact</li>
<li>There is a force upon contact but not before and after (constant velocity)</li>
<li>Change in direction, same speed, change in velocity</li>
<li>Car maintains the same energy</li>
</ul>
<p>Our model cannot be based on Energy or Speed. It must be based on directional velocity (+ or –). There will be more change if the car starts and bounces back rather than start and stop.</p>
<p>Using our data we came up with the following equations:</p>
<p><a href="http://levya11.files.wordpress.com/2010/02/impulse-info.jpg"><img class="aligncenter size-full wp-image-72" title="Velocity and Impulse" src="http://levya11.files.wordpress.com/2010/02/impulse-info.jpg?w=470" alt=""   /></a>From that we established that there is a direct relationship: The higher the impulse, the higher the ∆v. Furthermore, the slope of the graphs (see below) is equal to the mass. From these conclusions we came up with the equation for impulse:</p>
<ul>
<li>Impulse = mass • ∆v</li>
</ul>
<p><a href="http://levya11.files.wordpress.com/2010/02/graphs-for-impulse-with-25kg-and-75kg.jpg"><img class="aligncenter size-medium wp-image-73" title="Graphs for Impulse with .25kg and .75kg" src="http://levya11.files.wordpress.com/2010/02/graphs-for-impulse-with-25kg-and-75kg.jpg?w=204&#038;h=300" alt="" width="204" height="300" /></a></p>
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			<media:title type="html">Velocity and Impulse</media:title>
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		<title>Notes on reading 8.5-8.6</title>
		<link>http://levya11.wordpress.com/2010/02/02/notes-on-reading-8-5-8-6/</link>
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		<pubDate>Wed, 03 Feb 2010 03:18:29 +0000</pubDate>
		<dc:creator>levya11</dc:creator>
				<category><![CDATA[Physics]]></category>
		<category><![CDATA[Chapter 8]]></category>

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		<description><![CDATA[Chapter 8: Energy 8.5     Kinetic Energy Kinetic Energy (KE) &#8211; Energy of motion (motion capable of doing work). Kinetic energy = 1/2 mass • speed KE = 1/2 mv^2 KE is equal to the work required to bring the speed from rest. net force • distance = kinetic energy Fd = 1/2 mv^2 Work-energy theorem [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=levya11.wordpress.com&amp;blog=10571445&amp;post=69&amp;subd=levya11&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><strong>Chapter 8: Energy</strong></p>
<p><span style="text-decoration:underline;">8.5     Kinetic Energy</span></p>
<p>Kinetic Energy (KE) &#8211; Energy of motion (motion capable of doing work).</p>
<ul>
<li>Kinetic energy = 1/2 mass • speed</li>
<li>KE = 1/2 mv^2</li>
<li>KE is equal to the work required to bring the speed from rest.</li>
<li>net force • distance = kinetic energy</li>
<li>Fd = 1/2 mv^2</li>
</ul>
<p>Work-energy theorem &#8211; Work = ∆E</p>
<p><span style="text-decoration:underline;">8.6     Conservation of Energy</span></p>
<ul>
<li>Understanding how energy transforms is more important than being able to define energy &#8211; this is most easily accomplished by analyzing the transformation of one form of energy to another form of energy.</li>
<li>Energy transforms without net loss or net gain.</li>
</ul>
<p>Law of conservation of energy &#8211; Energy cannot be created or destroyed. It can be transformed from one form to another, but the total amount of energy never changes.</p>
<p>Thermonuclear Fusion &#8211; high-temperature welding of atomic nuclei.</p>
<ul>
<li>Releases radiant energy &#8211; some reaches Earth, other falls on plants (turning some to coal).</li>
<li>Sun&#8217;s energy is used to evaporate water from the ocean &#8211; Circle of life and nature.</li>
</ul>
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		<title>Class Discussion on 1/20</title>
		<link>http://levya11.wordpress.com/2010/01/21/class-discussion-on-120/</link>
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		<pubDate>Thu, 21 Jan 2010 18:32:27 +0000</pubDate>
		<dc:creator>levya11</dc:creator>
				<category><![CDATA[Physics]]></category>
		<category><![CDATA[Lab]]></category>

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		<description><![CDATA[Board Meeting Conclusions: The force graph from the ∆Distance and Force Lab has a linear trend line and a direct relationship. The energy graph from the ∆Distance and Energy Lab can use either a Power or Polynomial graph, meaning that it is a squared graph. From the Distance/Force lab our stiffness constant was 28.95 N/m [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=levya11.wordpress.com&amp;blog=10571445&amp;post=62&amp;subd=levya11&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>Board Meeting Conclusions:</p>
<ul>
<li>The force graph from the ∆Distance and Force Lab has a linear trend line and a direct relationship.</li>
<li>The energy graph from the ∆Distance and Energy Lab can use either a Power or Polynomial graph, meaning that it is a squared graph.</li>
<li>From the Distance/Force lab our stiffness constant was 28.95 N/m (after converting from cm) and our coefficient for the Distance/Energy graph was 13.651 N/m (approximately half) which helps prove the following:</li>
</ul>
<ul>
<li><a href="http://levya11.files.wordpress.com/2010/01/e28886e-equation.jpg"><img class="aligncenter size-full wp-image-63" title="∆E(spring) equation" src="http://levya11.files.wordpress.com/2010/01/e28886e-equation.jpg?w=470" alt=""   /></a>We also determined encountering a constantly increasing force creates the same issue with equatoins that constant acceleration did. Because of this we do not have a simple equation like work = force • distance, we have the more complex equation listed above.</li>
</ul>
<p>Our Board:</p>
<p><a href="http://levya11.files.wordpress.com/2010/01/1-20-bm.jpg"><img class="aligncenter size-medium wp-image-65" title="1-20 Board Meeting Board" src="http://levya11.files.wordpress.com/2010/01/1-20-bm.jpg?w=300&#038;h=225" alt="" width="300" height="225" /></a></p>
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			<media:title type="html">∆E(spring) equation</media:title>
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		<title>Class Discussion on 1/15</title>
		<link>http://levya11.wordpress.com/2010/01/18/class-discussion-on-115/</link>
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		<pubDate>Tue, 19 Jan 2010 04:21:08 +0000</pubDate>
		<dc:creator>levya11</dc:creator>
				<category><![CDATA[Physics]]></category>
		<category><![CDATA[Lab]]></category>

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		<description><![CDATA[Lab: Take a spring and apply a force, record how much the spring stretches. Find the relationship between the force you apply to the spring and how much the spring stretches. Data: Trial Distance (cm) Force (N) 1 27.8-22.5= 5.3 2 2 35-22.5= 12.5 4 3 42.7-22.5= 20.2 6 4 48.8-22.5= 26.3 8 5 56.5-22.5= [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=levya11.wordpress.com&amp;blog=10571445&amp;post=54&amp;subd=levya11&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><span style="text-decoration:underline;">Lab:</span> Take a spring and apply a force, record how much the spring stretches. Find the relationship between the force you apply to the spring and how much the spring stretches.</p>
<p><span style="text-decoration:underline;">Data:</span></p>
<table style="height:98px;" border="1" cellspacing="0" cellpadding="0" width="280">
<tbody>
<tr>
<td width="46" valign="top">Trial</td>
<td width="99" valign="top">Distance (cm)</td>
<td width="68" valign="top">Force (N)</td>
</tr>
<tr>
<td width="46" valign="top">1</td>
<td width="99" valign="top">27.8-22.5= 5.3</td>
<td width="68" valign="top">2</td>
</tr>
<tr>
<td width="46" valign="top">2</td>
<td width="99" valign="top">35-22.5= 12.5</td>
<td width="68" valign="top">4</td>
</tr>
<tr>
<td width="46" valign="top">3</td>
<td width="99" valign="top">42.7-22.5= 20.2</td>
<td width="68" valign="top">6</td>
</tr>
<tr>
<td width="46" valign="top">4</td>
<td width="99" valign="top">48.8-22.5= 26.3</td>
<td width="68" valign="top">8</td>
</tr>
<tr>
<td width="46" valign="top">5</td>
<td width="99" valign="top">56.5-22.5= 34</td>
<td width="68" valign="top">10</td>
</tr>
</tbody>
</table>
<p>To begin with, our spring was 22.5cm long. In the &#8220;Distance&#8221; column we subtracted 22.5cm from the distance that the spring reached after the specified force was applied. We did this to find the &#8220;stretchiness&#8221; or change in distance so that we were able to record concise data.</p>
<p><span style="text-decoration:underline;">Graph:</span></p>
<p><a href="http://levya11.files.wordpress.com/2010/01/distance-versus-force-graph.jpg"><img class="aligncenter size-medium wp-image-67" title="Distance versus Force Graph" src="http://levya11.files.wordpress.com/2010/01/distance-versus-force-graph.jpg?w=300&#038;h=177" alt="" width="300" height="177" /></a></p>
<p><span style="text-decoration:underline;">Conclusions: </span></p>
<ul>
<li>Slope of the graph = &#8220;Stretchiness&#8221; &#8211; For every 1 N, the spring stretches 3.56cm</li>
<li>The larger the coefficient of the equation of the line on the graph, the more stretched out the spring was to begin with.</li>
<li>Spring Stiffness is represented by the equation: F = k d + 0     (F = force, k = stiffness, d = distance)</li>
</ul>
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			<media:title type="html">Distance versus Force Graph</media:title>
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		<title>Notes on reading 8.1-8.4</title>
		<link>http://levya11.wordpress.com/2010/01/18/notes-on-reading-8-1-8-4/</link>
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		<pubDate>Tue, 19 Jan 2010 03:52:42 +0000</pubDate>
		<dc:creator>levya11</dc:creator>
				<category><![CDATA[Physics]]></category>
		<category><![CDATA[Chapter 8]]></category>

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		<description><![CDATA[Chapter 8: Energy 8.1     Work Work &#8211; Quantity (distance) of force x distance. Application of a force and the movement of something by the force are componets of every case where work is done. Work = f d     (work = force x distance) Work is measured in one of two ways: Newton-meter (N•m) Joule (J)     [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=levya11.wordpress.com&amp;blog=10571445&amp;post=52&amp;subd=levya11&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><strong>Chapter 8: Energy</strong></p>
<p><span style="text-decoration:underline;">8.1     Work</span></p>
<p>Work &#8211; Quantity (distance) of force x distance.</p>
<ul>
<li>Application of a force and the movement of something by the force are componets of every case where work is done.</li>
<li>Work = f d     (work = force x distance)</li>
</ul>
<p>Work is measured in one of two ways:</p>
<ol>
<li>
<div>Newton-meter (N•m)</div>
</li>
<li>Joule (J)     [Named after James Joule]</li>
</ol>
<ul>
<li>One joule of work is done when a force of 1 N is applied over a distance of 1 meter.</li>
</ul>
<p><span style="text-decoration:underline;">8.2     Power</span></p>
<p>Power &#8211; The rate at which work is done.</p>
<ul>
<li>Power = (work done) / (time interval)</li>
</ul>
<p>Watt &#8211; The power expended when one joule of work is done in one second.</p>
<p><span style="text-decoration:underline;">8.3     Mechanical Energy</span></p>
<p>Energy &#8211; &#8220;Something&#8221; that enables an object to do work.</p>
<ul>
<li>Measured in joules</li>
</ul>
<p>Mechanical Energy &#8211; The energy due to the position of something or movement of something.</p>
<p><span style="text-decoration:underline;">8.4     Potential Energy</span></p>
<p>Potential Energy (PE) &#8211; Energy that is stored and held in readiness.</p>
<ul>
<li>Gravitational Potential Energy = Weight x Height     (PE = mg h)</li>
</ul>
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		<title>Notes on reading 11.4-11.7</title>
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		<pubDate>Tue, 19 Jan 2010 03:26:37 +0000</pubDate>
		<dc:creator>levya11</dc:creator>
				<category><![CDATA[Physics]]></category>
		<category><![CDATA[Chapter 11]]></category>

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		<description><![CDATA[Chapter 11:Rotational Mechanics 11.4     Rotational Inertia Rotational Inertia (Moment of Inertia) &#8211; The resistance of an object to changes in its rotational motion. Rotating objects keep rotating, stationary objects stay stationary. Depends on mass and distribution of the mass. Larger distance between the bulk of the mass and the axis of rotation creates a larger [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=levya11.wordpress.com&amp;blog=10571445&amp;post=45&amp;subd=levya11&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><strong>Chapter 11:Rotational Mechanics<br />
</strong></p>
<p><span style="text-decoration:underline;">11.4     Rotational Inertia<br />
</span></p>
<p>Rotational Inertia (Moment of Inertia) &#8211; The resistance of an object to changes in its rotational motion.</p>
<ul>
<li>Rotating objects keep rotating, stationary objects stay stationary.</li>
<li>Depends on mass and distribution of the mass.</li>
<li>Larger distance between the bulk of the mass and the axis of rotation creates a larger rotational inertia.</li>
<li>I = mr^2     (inertia = mass x rotational axis)</li>
</ul>
<p><span style="text-decoration:underline;">11.5     Rotational Inertia and Gymnastics<br />
</span></p>
<ul>
<li>The human body has many axes of symmetry. Rotational inertia differs upon each axis. Rotatioal inertia is about the transverse and median axes.</li>
</ul>
<p><span style="text-decoration:underline;">11.6     Angular Momentum<br />
</span></p>
<p>Linear Momentum &#8211; &#8220;Inertia of motion&#8221; or momentum (mass x velocity).</p>
<ul>
<li>Linear momentum = mass x velocity</li>
</ul>
<p>Angular Momentum &#8211; &#8220;Inertia of rotation&#8221; or rotation of objects.</p>
<ul>
<li>Angular Momentum = Rotational inertia x Rotational velocity</li>
<li>Angular Momentum = I ω</li>
<li>Angular Momentum = mv r     (magnitude of linear momentum x radial distance)</li>
</ul>
<p>Rotational Velocity &#8211; A direction that is assigned to rotational speed.</p>
<ul>
<li>Similarly to linear momentum, angular momentum is a vector quantity (has direction AND magnitude).</li>
</ul>
<p><span style="text-decoration:underline;">11.7     Conservation of Angular Momentum<br />
</span></p>
<p>Law of conservation of angular momentum &#8211; If no unbalanced external torque acts on a rotating system, the angular momentum of that system is constant.</p>
<ul>
<li>No external torque means the product of rotational inertia and rotational velocity will, at one time, be the same at any other time.</li>
</ul>
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		<title>Notes on reading 9.1-9.3</title>
		<link>http://levya11.wordpress.com/2010/01/13/notes-on-9-1-9-3/</link>
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		<pubDate>Wed, 13 Jan 2010 16:12:59 +0000</pubDate>
		<dc:creator>levya11</dc:creator>
				<category><![CDATA[Physics]]></category>
		<category><![CDATA[Chapter 9]]></category>

		<guid isPermaLink="false">http://levya11.wordpress.com/?p=41</guid>
		<description><![CDATA[Chapter 9: Circular Motion 9.1     Rotation and Revolution Axis &#8211; The straight line around which rotation takes place. Rotation (spin) &#8211; When an object turns about an internal axis. Revolution &#8211; When an object turns about an external axis. 9.2     Rotational Speed Linear Speed &#8211; Distance moved per unit of time. Tangential Speed &#8211; The [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=levya11.wordpress.com&amp;blog=10571445&amp;post=41&amp;subd=levya11&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p><strong>Chapter 9: Circular Motion</strong></p>
<p><span style="text-decoration:underline;">9.1     Rotation and Revolution</span></p>
<p>Axis &#8211; The straight line around which rotation takes place.</p>
<p>Rotation (spin) &#8211; When an object turns about an internal axis.</p>
<p>Revolution &#8211; When an object turns about an external axis.</p>
<p><span style="text-decoration:underline;">9.2     Rotational Speed</span></p>
<p>Linear Speed &#8211; Distance moved per unit of time.</p>
<p>Tangential Speed &#8211; The speed of something moving along a circular path.</p>
<p>Rotational Speed &#8211; The number of rotations per unit of time.</p>
<ul>
<li>Tangential speed ~ radial distance • rotational speed</li>
</ul>
<p><span style="text-decoration:underline;">9.3     Centripetal Force</span></p>
<p>Centripetal Force &#8211; Any force that causes an object fo follow a circular path.</p>
<p>When examining the movements of the ice skater, we concluded that it is not the angular speed that effects her movement, it is the linear speed.</p>
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		<title>Curveball Predicament 12/9</title>
		<link>http://levya11.wordpress.com/2009/12/13/curveball-predicament-129/</link>
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		<pubDate>Sun, 13 Dec 2009 20:55:00 +0000</pubDate>
		<dc:creator>levya11</dc:creator>
				<category><![CDATA[Physics]]></category>
		<category><![CDATA[Chapter 3]]></category>

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		<description><![CDATA[We were assigned to find a head-on video of a curve ball (such as a baseball being thrown) and to collect data for the throw. Our group discovered that we cannot collect data with a video like this or a side-view video because head-on, we do not have a consistent scale due to the ball [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=levya11.wordpress.com&amp;blog=10571445&amp;post=38&amp;subd=levya11&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>We were assigned to find a head-on video of a curve ball (such as a baseball being thrown) and to collect data for the throw. Our group discovered that we cannot collect data with a video like this or a side-view video because head-on, we do not have a consistent scale due to the ball getting larger as it moves closer to the camera. With the side-view video, we cannot track the change in motion of the ball while it is moving. We would need a bird&#8217;s-eye view video to accurately collect data to create graphs. Instead, we talked about how the path of the ball differs when the ball is smooth or when it has stitching as well as how the wind affects both scenarios. We then came up with this picture:</p>
<p><a href="http://levya11.files.wordpress.com/2009/12/9.jpg"><img class="aligncenter size-medium wp-image-39" title="Curveball 12/9" src="http://levya11.files.wordpress.com/2009/12/9.jpg?w=230&#038;h=300" alt="" width="230" height="300" /></a></p>
<p>This demonstrates that the right side of the ball is moving further than the left at any given time.</p>
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			<media:title type="html">Curveball 12/9</media:title>
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		<title>Class Discussion on 12/8</title>
		<link>http://levya11.wordpress.com/2009/12/13/class-discussion-on-128/</link>
		<comments>http://levya11.wordpress.com/2009/12/13/class-discussion-on-128/#comments</comments>
		<pubDate>Sun, 13 Dec 2009 20:44:46 +0000</pubDate>
		<dc:creator>levya11</dc:creator>
				<category><![CDATA[Physics]]></category>
		<category><![CDATA[Chapter 20]]></category>
		<category><![CDATA[Chapter 5]]></category>
		<category><![CDATA[WebQuest]]></category>

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		<description><![CDATA[Board Meeting Conclusions: Air pressure: molecules and oxygen colliding together &#8211; they become faster and react with one another. If air pressure in a container is less then the atmospheric pressure must be greater in order to allow it to close in on a box (collapse). As temperature increases, pressure increases (direct relationship). As density [...]<img alt="" border="0" src="http://stats.wordpress.com/b.gif?host=levya11.wordpress.com&amp;blog=10571445&amp;post=36&amp;subd=levya11&amp;ref=&amp;feed=1" width="1" height="1" />]]></description>
			<content:encoded><![CDATA[<p>Board Meeting Conclusions:</p>
<ul>
<li>Air pressure: molecules and oxygen colliding together &#8211; they become faster and react with one another.</li>
<li>If air pressure in a container is less then the atmospheric pressure must be greater in order to allow it to close in on a box (collapse).</li>
<li>As temperature increases, pressure increases (direct relationship).</li>
<li>As density decreases, pressure increases (indirect relationship).</li>
<li>As volume decreases, pressure increases (indirect relationship).</li>
<li>As speed increases, volume decreases (indirect relationship).</li>
<li>We don&#8217;t &#8220;burst&#8221; because the pressure inside us equals that of the pressure challenging us.</li>
<li>When traveling below the surface (in water) the pressure increases at a fairly constant rate.</li>
<li>Air is considered fluid (generic term for gases and liquids) in terms of Physics.</li>
</ul>
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